下面 count_triple 函数的时间复杂度为( )。
nt count_triple(int n) { int cnt = 0; for (int a = 1; a <= n; a++) for (int b = a; a + b <= n; b++) for (int c = b; a + b + c <= n; c++) if (a * a + b * b == c * c) cnt++; return cnt; }
O(N)
O(N2)
O(N3)
O(N4)