下面 search 函数的平均时间复杂度为( )。
int search(int n, int * p, int target) { int low = 0, high = n; while (low <= high) { int middle = (low + high) / 2; if (target == p[middle]) { return middle; } else if (target > p[middle]) { low = middle + 1; } else { high = middle - 1; } } return -1; }
O(n)
O(log(n))
O(1)
可能无法返回