单选题

二叉搜索树中的每个结点,其左子树的所有结点值都小于该结点值,右子树的所有结点值都大于该结点值。以下代码对给定的整数数组(假设数组中没有数值相等的元素),构造一个对应的二叉搜索树,横线上应填写(    ):

class TreeNode:

      def __init__(self, x):

            self.val = x

            self.left = None

            self.right = None


class Solution:

      def isValidBST(self, root: TreeNode) -> bool:

            def helper(node, min_val, max_val):

                  if not node:

                        return True

                  ————————————

                        return False

                  return helper(node.left, min_val, node.val) and helper(node.right,

node.val, max_val)

              return helper(root, float('-inf'), float('inf'))

A

if node.val <= min_val="" or="" node.val="">= max_val:

B

if node.val >= min_val or node.val >= max_val:

C

if node.val <= min_val or node.val <= max_val:

D

if node.val >= min_val or node.val <= max_val:

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